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AskSQLTeam
Ask SQLTeam Question
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Posted - 2006-08-10 : 09:41:46
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| Tesfa writes "I am a Crystal Reports 11 user that is creating a report based on a view I created. What happens with the view is I will have the same case number (used to identify the customer) that has a contact information and contractor information. When I created the SQL view, SQL Server 2005 sees two of the same case number but on two record that have contract information and the other has the contractor information. When I run the report it multiples the pages, if there is a Case Number without contractor info it makes my two page report which I want. Visual example below of View ResultsetCase# ContactFirst ContactLast ContractorName ContractorType1100 Tom William Null Null1100 Null Null FF Labor Sub_ContractorThis is a simple example of what I am facing. Technically thats correct but Crystal doesnt like it. Question: Is there a way where I can combine only the Contractor information to the record set that has the Contact information. I tried Concatenation but realize I need to still use the columns in Crystal Reports. Example of what I am looking for:Case# ContactFirst ContactLast ContractorName ContractorType1100 Tom William FF Labor Sub_ContractorThats how the application the clients use sees it and it works for Crystal Reports. Thanks. I am a Sams 21 days of SQL Server 2000 - 2005 and not bad with writing the code but I have fellow programmers that can help me understand your solution if your able to find one. Thanks again." |
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DonAtWork
Master Smack Fu Yak Hacker
2167 Posts |
Posted - 2006-08-10 : 10:40:19
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| Follow the first link in my sig and try restating your question.For fast help, follow this link:http://weblogs.sqlteam.com/brettk/archive/2005/05/25.aspxLearn SQLhttp://www.sql-tutorial.net/ http://www.firstsql.com/tutor.htm http://www.w3schools.com/sql/default.asp |
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khtan
In (Som, Ni, Yak)
17689 Posts |
Posted - 2006-08-11 : 01:31:26
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[code]select [Case#], max(ContactFirst), max(ContactLast), max(ContractorName), max(ContractorType)from tablegroup by [Case#][/code] KH |
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