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AskSQLTeam
Ask SQLTeam Question
0 Posts |
Posted - 2005-12-13 : 07:39:18
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| Gennady writes "If I do have an array with 12 parameters on it@Array = ‘1,2,3,4,5,6,7,8,9,10,11,12’ or@Araay = 'A, B, C, D, E, F, G, Z, H, K, L, M, W, J'What I try to do that be able to find a number 6 in my array list, and also I want to loop from that position 6 times. What I am saying that I would be able to find a start point, which is 6, and recreate an array so it will be looking like:@Array =’6,7,8,9,10,11’Please help me if you have any ideas" |
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madhivanan
Premature Yak Congratulator
22864 Posts |
Posted - 2005-12-13 : 08:09:43
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| Is this?Declare @Array varchar(100)set @Array = '1,2,3,4,5,6,7,8,9,10,11,12'Select substring(@Array,charindex('6',@Array),len(@Array))What do you want to do?MadhivananFailing to plan is Planning to fail |
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