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                                         MRIGUY 
                                        Starting Member 
                                         
                                        
                                        17 Posts  | 
                                        
                                        
                                            
                                            
                                             Posted - 2002-02-07 : 17:10:17
                                            
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                                            | I'm want to write a formula that conditionally uses members.  Some cubes may have the member and some may not.  So if [MemberA] exists use it otherwise use [MemberB]As soon as I reference [MemberA] in a cube that doesn't have it, error.Is there a function that can be used to check if a member exists?  | 
                                             
                                         
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                                     Mandolino 
                                    Starting Member 
                                     
                                    
                                    1 Post  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2003-03-31 : 06:51:08
                                          
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                                          | Hello,You may use the Name property of a member.Here is an example:Sum(Filter([Language].[Language Code].Members,[Language].CurrentMember.Name="en"))In your case: <...>.Name="MemberA"  | 
                                         
                                        
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                                     robvolk 
                                    Most Valuable Yak 
                                     
                                    
                                    15732 Posts  | 
                                    
                                      
                                        
                                          
                                           
                                            Posted - 2003-03-31 : 07:11:41
                                          
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                                          quote: Checking for existence of a member
  Never mind, I was thinking of something else.     | 
                                         
                                        
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