WHERE someField IN (@test) - SQL Server Forums

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WHERE someField IN (@test)

Author

Topic

Zath
Constraint Violating Yak Guru

298 Posts

Posted - 2009-07-22 : 09:07:32

A parameter is a list, or string, of ints.

Doing a simple select using IN but this breaks....

DECLARE @test VARCHAR(256)
SET @test = '1303, 1308, 1309, 1305, 1311, 1307, 1313, 1306, 1312 '

SELECT * FROM myTable WHERE myIntField IN (@test)

Syntax error converting the varchar value '1303, 1308, 1309, 1305, 1311, 1307, 1313, 1306, 1312 ' to a column of data type int.

Should there be a convert here?

Thanks,

Zath

khtan
In (Som, Ni, Yak)

17689 Posts

Posted - 2009-07-22 : 09:12:05

http://vyaskn.tripod.com/passing_arrays_to_stored_procedures.htm
http://www.sommarskog.se/arrays-in-sql-2000.html

KH
[spoiler]Time is always against us[/spoiler]

bklr
Master Smack Fu Yak Hacker

1693 Posts

Posted - 2009-07-23 : 00:19:31

try any one of these


DECLARE @test VARCHAR(256)
SET @test = '1303, 1308, 1309, 1305, 1311, 1307, 1313, 1306, 1312 '

SELECT * FROM myTable where '%,' + @test+ ',%' LIKE '%,' + CAST( myIntField  AS VARCHAR(255)) +',%' 

exec('select * from mytable where  CAST( myIntField  AS VARCHAR(255)) in('+@test+')')

SELECT * FROM myTable where patindex('%,' + CAST( empid AS VARCHAR(255)) +',%',','+@test+',' )>0

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