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AskSQLTeam
Ask SQLTeam Question
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Posted - 2001-06-29 : 09:41:25
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| Cindy writes "We are unable to add new record in a table where we have defined the seed value. I have made up a example below to show you the problem we are having, Your cooperation is needed desperately. ----------------table structure --------------- In a Sql database table column name= id ,Datatype = integer , length=4 ,precision=10, allownull=not checked , identity=check marked , identity seed = 1 , identity increment=1 ------------------------------------------------------- I wanted SQl to insert value in id field by autoincrement. id field is structured to add by sed value as mentioned in my earlier message ************Error we get********* Error Type: ADODB.Recordset (0x800A0BB9) Arguments are of the wrong type, are out of acceptable range, or are in conflict with one another. /o/problem/receive.asp, line 15 ************************************ ************Actual coding of recieve.asp below is line# 1******* @ Language=VBScript response.buffer=true dim con set con=server.createobject("ADODB.connection") con.open application("mydsn") ... Sender=request.form("T1") set rs=server.createobject("ADODB.recordset") sql="select * from subemail " rs.open sql,con,4,3 rs.addnew rs("email")=sender rs("ipenter")=request.servervariables("REMOTE_ADDR") rs("cdate")=date() rs.update *****error we got is on the line 15 where it says : rs.open sql,con,4,3 ************* ------------------ This is latest error update of my yesterday messages at : http://www.aspmessageboard.com/forum/databases.asp?M=246520&P=1&F=21 -------------------------- ******** (mydsn): we have defined in global.asa this connection and gave the name of the database to connect to for dsn less connections. ********* why i am geting problem in my line 15 what is the problem with above coding. This problem is not solved on 4guysfromrolla.comhttp://www.aspmessageboard.com/forum/asp.asp?M=246667&F=20&P=1& expert-resources.com if you at sqlteam.com can solve it , i will be a slave for you guys. any geek wanna help plz. Please help, desperado. Mucho Gracias Cindy " |
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