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                                | Author | Topic |  
                                    | leo_ultra_leoStarting Member
 
 
                                        2 Posts | 
                                            
                                            |  Posted - 2012-06-04 : 05:57:08 
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                                            | Hi folks,I have two table, the first one name is basetab1 and the second is basetab2, as the following:Table1:select usertype Brands, count(*) Subscriber from basetab1group by usertypeorder by usertype brands     subscriber ---------  ------------- 0          29029 1          2 2          21 3          175 4          467Table2select subtype ,subtypename from basetab2 isdntype     isdntypename -----------  ---------------------------- 0            Default 1            Employee 2            Test 3            Test2 4            PrivateQuestion is, how can I get such result in one query:isdntypename         Subscriber -----------       ------------- Default               29029 Employee              2 Test                  21 Test2                 175 Private               467I've tried these syntaxes but I've filed to get a quesryFirst Syntax: select isdntypename, count(*) MSISDNfor basetab1.usertype=basetab2.isdntypenamegroup by usertypeSecond Syntax: select isdntypename, count(msisdn) MSISDNfor basetab1 inner join basetab2 on (basetab1.usertype=basetab2.isdntypename)group by usertypeYour HELP please! |  |  
                                    | visakh16Very Important crosS Applying yaK Herder
 
 
                                    52326 Posts | 
                                        
                                          |  Posted - 2012-06-04 : 10:29:04 
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                                          | [code]select isdntypename, Subscriber from(select usertype Brands, count(*) Subscriber from basetab1group by usertype)t1join basetab2 t2on t2.isdntype  = t1.brandsorder by brands[/code]------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ |  
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                                    | leo_ultra_leoStarting Member
 
 
                                    2 Posts | 
                                        
                                          |  Posted - 2012-06-05 : 02:54:40 
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                                          | Thanks dear, but didn't work as well  .  please remember this DB is informix not oracle.  However, thanks for your effortCheers quote:Originally posted by visakh16
 
 select isdntypename, Subscriber from(select usertype Brands, count(*) Subscriber from basetab1group by usertype)t1join basetab2 t2on t2.isdntype  = t1.brandsorder by brands------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ 
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                                    | visakh16Very Important crosS Applying yaK Herder
 
 
                                    52326 Posts | 
                                        
                                          |  Posted - 2012-06-05 : 12:41:15 
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                                          | quote:then you should be posting it in some informix forumthis is ms sql server forum so i'm not sure there're any informix experts out here to help you with specific syntax help------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/Originally posted by leo_ultra_leo
 Thanks dear, but didn't work as well
  .  please remember this DB is informix not oracle.  However, thanks for your effortCheers quote:Originally posted by visakh16
 
 select isdntypename, Subscriber from(select usertype Brands, count(*) Subscriber from basetab1group by usertype)t1join basetab2 t2on t2.isdntype  = t1.brandsorder by brands------------------------------------------------------------------------------------------------------SQL Server MVPhttp://visakhm.blogspot.com/ 
    
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                                    | domusonlineStarting Member
 
 
                                    1 Post | 
                                        
                                          |  Posted - 2012-06-07 : 10:09:09 
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                                          | I'm not sure if my latest reply attemp will go through or not. It yes, please apologize for the duplicate:The problem with the inline table is not that this is Informix. It's the version of Informix. Versions before 11 could use it but with a non-standard syntax.In any case, the following query will work on any database:SELECT        subtypename, COUNT(*)FROM        basetab1 a, basetab2 bWHERE        a.usertype = b.subtypeGROUP BY subtypenameORDER BY subtypename;There will be some problems if not all the records in basetab1 have a match in basetab2 (an outer join could be used if those records would need to be seen)Also, there are some errors and incongruence in the original post ("for "?... SELECT subtype and then the result set shows isdntype?)Regards and HTH |  
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