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shemayb
Posting Yak Master
159 Posts |
 Posted - 2007-09-26 : 21:22:17
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| What is the process of subtracting values(Date Values) in a textbox?Funnyfrog |
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shemayb
Posting Yak Master
159 Posts |
Posted - 2007-09-26 : 21:42:09
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| Datediff function in c#.Funnyfrog |
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rrb
SQLTeam Poet Laureate
1479 Posts |
Posted - 2007-09-26 : 21:48:46
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Hey funnyfrogam i missing something. I also have some questions I could answer myself.... Actually I know a joke like that - "Why do firemen wear red braces to hold their trousers up?"--I hope that when I die someone will say of me "That guy sure owed me a lot of money" |
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shemayb
Posting Yak Master
159 Posts |
Posted - 2007-09-26 : 21:53:36
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| is there a datediff function in c#?Funnyfrog |
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rrb
SQLTeam Poet Laureate
1479 Posts |
Posted - 2007-09-26 : 22:00:38
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| Ah - my apologies, I didn't understand what you were asking...check these[url]http://www.dotnetspider.com/kb/Article1552.aspx[/url][url]http://www.devnewsgroups.net/group/microsoft.public.dotnet.framework/topic11262.aspx[/url][url]http://www.aspcode.net/C-Datediff.aspx[/url]let us know if that's not what you're after--I hope that when I die someone will say of me "That guy sure owed me a lot of money" |
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shemayb
Posting Yak Master
159 Posts |
Posted - 2007-09-26 : 22:05:20
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| it's ok...thank you..How about if i have time values in my textbox and i want that my endtime will be subtracted to my strttime and then divide it by 60?is there a way for me to do that in c#?Funnyfrog |
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rrb
SQLTeam Poet Laureate
1479 Posts |
Posted - 2007-09-26 : 22:14:51
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You mean something different to thisDateTime start = some value; DateTime end = some other value; TimeSpan diff = start - end; hours = diff.TotalHours; ?--I'm not schooled in the science of human factors, but I suspect that surprise is not an element of a robust user interface. |
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shemayb
Posting Yak Master
159 Posts |
Posted - 2007-09-26 : 22:23:20
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| if i divide it with 60 can i put it like that of the ff?DateTime start = some value; DateTime end = some other value; TimeSpan diff = (start - end/60);(newly added) hours = diff.TotalHours;Funnyfrog |
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rrb
SQLTeam Poet Laureate
1479 Posts |
Posted - 2007-09-26 : 22:29:21
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| I don't think what you've added makes any sense. Why are you dividing by 60? diff.TotalHours is already in hours. What are you trying to calculate?--I'm not schooled in the science of human factors, but I suspect that surprise is not an element of a robust user interface. |
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shemayb
Posting Yak Master
159 Posts |
Posted - 2007-09-26 : 22:31:10
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| i added that because that is the formula that i needed to calculate the total time.Funnyfrog |
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rrb
SQLTeam Poet Laureate
1479 Posts |
Posted - 2007-09-26 : 22:36:21
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Yep, but what I'm saying is that diff.totalHours is already the total time. You don't need to divide by 60. Normally you divide by 60 if you were given the answer as minutes.So if you really want to divide something by sixty, you could change the code like this TimeSpan diff = start - end; Double hours = diff.TotalMinutes/60; Is that what you're after?--I'm not schooled in the science of human factors, but I suspect that surprise is not an element of a robust user interface. |
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subtracting values in a textbox