How to create a file with Header, details & footer

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How to create a file with Header, details & footer

Author

Topic

asbharadwaj
Starting Member

27 Posts

Posted - 2006-08-31 : 04:16:33

Hi All,

I need to create a query which gives me something like this

HH20060831160342
DDasb IT 3000
FF20060831160709000000001

Where 'HH' is the header(followed by Date and time) and 'FF' is the footer (followed by Date, time and no of records)and 'DD' has some details (few fields) from database.I am using UNION to get this result but the problem is that if the count in the footer is 0 then query should not give any output.but If I am using the following query
select 'HH'+convert(varchar,getDATE(),112)+replace(convert(varchar,getdate(),8),':','') as filename,'' as name,'' as dept,'' as sal
union all
select 'DD'+'',filename,dept,sal from emp where empno like '%1%'
union all
select 'FF'+convert(varchar,getDATE(),112)+replace(convert(varchar,getdate(),8),':','')+ REPLICATE(0, 9-len(COUNT(*)))+''+convert(VARchar(10),COUNT(*)) as filename,'' as name,'' as dept,'' as sal from emp where empno like '%1%'

I am getting the result as

HH20060831161226
FF20060831161226000000000
if the second select statement has no records

Please help

khtan
In (Som, Ni, Yak)

17689 Posts

Posted - 2006-08-31 : 04:41:11

for this query

select 'DD'+'',filename,dept,sal from emp where empno like '%1%'

shouldn't it ibe

select 'DD' + filename + dept + convert(varchar(10), sal) from emp

SwePeso
Patron Saint of Lost Yaks

30421 Posts

Posted - 2006-08-31 : 05:22:50

Or something like this?

IF EXISTS (SELECT * FROM Emp WHERE EmpNo LIKE '%1%')
	SELECT		'HH' + CONVERT(varchar, GETDATE(), 112) + REPLACE(CONVERT(varchar, GETDATE(), 8), ':', '') AS Filename,
			'' AS Name,
			'' AS Dept,
			'' AS Sal
	UNION ALL
	SELECT		'DD',
			ISNULL(Filename, ''),
			ISNULL(Dept, ''),
			ISNULL(Sal, '')
	FROM		Emp
	WHERE		EmpNo LIKE '%1%'
	UNION ALL
	SELECT		'FF' + CONVERT(varchar, GETDATE(), 112) + 	REPLACE(CONVERT(varchar, GETDATE(), 8), ':', '') + RIGHT('0000000000' + CONVERT(varchar, COUNT(*)), 10)
			'',
			'',
			''
	FROM		Emp
	WHERE		EmpNo LIKE '%1%'

Peter Larsson
Helsingborg, Sweden

asbharadwaj
Starting Member

27 Posts

Posted - 2006-08-31 : 05:48:57

Thanks alot

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