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 Transact-SQL (2008)
 selecting the nearest date time
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silentbob
Starting Member

18 Posts

Posted - 03/26/2013 :  09:21:58  Show Profile  Reply with Quote
Hi

I have a table with 2 columns, one is datetime which there is an entry for each hour of the day (2013-03-25 01:00:00.000) and the other are values (real). I want to select the value in the forthcoming hour so if I ran the query now (13:20 uk time) it would show me the value at 14:00

Can anyone help.

James K
Flowing Fount of Yak Knowledge

3873 Posts

Posted - 03/26/2013 :  09:28:03  Show Profile  Reply with Quote
This?
select valuecol 
from YourTable
where hourColumn = DATEADD(hh,datediff(mi,0,GETDATE())/60+1,0);
--where hourColumn = DATEADD(hh,datediff(hh,0,GETDATE())+1,0); -- or perhaps this?
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silentbob
Starting Member

18 Posts

Posted - 03/26/2013 :  09:31:32  Show Profile  Reply with Quote
spot on thanks
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James K
Flowing Fount of Yak Knowledge

3873 Posts

Posted - 03/26/2013 :  11:18:41  Show Profile  Reply with Quote
You are very welcome - glad to help.

Check the boundary case where the current time is exactly on the hour whether it is giving you what you want. For example, this gives you 12:00 noon. Is that what you want?
select  DATEADD(hh,datediff(mi,0,'2013-03-26 11:00:00.000')/60+1,0);
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