Please start any new threads on our new site at http://forums.sqlteam.com. We've got lots of great SQL Server experts to answer whatever question you can come up with.

Our new SQL Server Forums are live! Come on over! We've restricted the ability to create new threads on these forums.

SQL Server Forums
Profile | Active Topics | Members | Search | Forum FAQ
 
Register Now and get your question answered!
Username:
Password:
Save Password
Forgot your Password?

 All Forums
 SQL Server 2008 Forums
 Transact-SQL (2008)
 distinct summing?
 Reply to Topic
 Printer Friendly
Author Previous Topic Topic Next Topic  

mmiddl
Starting Member

USA
1 Posts

Posted - 01/17/2013 :  13:51:02  Show Profile  Reply with Quote
I'm so stumped I can't even google this! I've got a distinct query figured out, but then I want to sum up one column in the query results & can't figure it out. Example:

select distinct t1.basket, t1.fruit, t1.qty, t2.size
from table1 t1, table2 t2
where t1.basket=t2.basketID

Table1

Basket/ Fruit/ Qty
1/ apple/ 10
1/ apple/ 10
1/ apple/ 1
2/ apple/ 2
3/ orange/ 3

Table 2
Basket/Size
1/small
2/medium
3/large

Qry results:
Basket/ Fruit/ Qty/ Size
1/ apple/ 10/ small
1/ apple/ 1/ small
2/ apple/ 2/ medium
3/ orange/ 3/ large

So the whole point of the distinct qry is that it removed that repeated result where we had basket 1 of 10 apples removed.

I WANT to find total of qty which=16.

any thoughts on how I can use SUM to add up the result of 10+1+2+3 and just return: 16 to me?

sodeep
Flowing Fount of Yak Knowledge

USA
7174 Posts

Posted - 01/17/2013 :  14:28:23  Show Profile  Reply with Quote
Select SUM(Qty)
from
(
Select distinct t1.basket, t1.fruit, t1.qty, t2.size
from table1 t1, table2 t2 
where t1.basket=t2.basketID
)P
Go to Top of Page
  Previous Topic Topic Next Topic  
 Reply to Topic
 Printer Friendly
Jump To:
SQL Server Forums © 2000-2009 SQLTeam Publishing, LLC Go To Top Of Page
This page was generated in 0.07 seconds. Powered By: Snitz Forums 2000